Yeah, my logic is flawed.
If it were 6 x 2 +4 that would be 16MB of level 2 cache, that's more than a 13500.
The 13500 has 6 P-cores also at 1.25MB, equal to 7.5MB. Then 8 E-cores, or two clusters (4 E-cores per cluster) at 2MB per cluster, for a total of 11.5MB.
My 13400 6 P-cores (7.5MB) plus...